Q: Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
- The number of elements initialized in nums1 and nums2 are m and n respectively.
- You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
I would add a requirement — O(1) additional space. so you can’t create another array. This can be realistic if allocation is strictly controlled to prevent fragmentation in embedded environment.
Rather contrived, so I won’t spend too much time
–Idea: use num1’s right portion as the “new” array.
Suppose the allocated array of num1 has capacity k >= m + n. I will call it array KK. Note The right portion of KK is currently unused, so I can wipe it clean with some dummy value.
( If no dummy value is possible, then I probably can still solve the problem but with less clarity. )
Now backscan both arrays and put the highest value in KK[m+n-1] , filling KK leftward. The spare capacity to the right of this position will remain unused forever.
Implementation note — We need a back-scanner pointer into num1 as “cur” + another pointer to the right, “lastPicked”… meaning the item at this position has been copied to KK.
(We may not need lastPicked pointer, but it is less ambiguous more clear, easier to reason with. You may say it’s a device for analysis and communication, not necessarily for coding.)
We also need such a pointer into num2.