longest consecutive ints ] matrix 70% done

View at Medium.com

Q: Given a n*n square matrix where all numbers are distinct, find the maximum length path (starting from any cell) such that all cells along the path are in increasing order with a difference of 1. We can move in 4 directions from a given cell (i, j), i.e., we can move to (i+1, j) or (i, j+1) or (i-1, j) or (i, j-1) with the condition that the adjacent cells have a difference of 1.


Input: mat[][] = {
{1, 2, 9}
{5, 3, 8}
{4, 6, 7}}
Output: 4
The longest path is 6-7-8-9.

–sol1, probably O(NN) since each node is checked no more than 5 times.

1) typewriter search for the first unvisited node. Exit if all visited. Once a node is found, designate it as cur.
2) down-search .. explore cur’s four neighbors to see if any == cur-1.
3) if found, then desingate that node as cur and continue the down-search.
4) At end of down-search, Go back to #2) and start up-search.
5) At end of up-search we have a linked list. IFF list size > 1, then all nodes on it are marked as visited.
7) go back to #1.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s