new-expression alloates AND invokes ctor…most of the time

Neither the allocation or the ctor step is universal and guaranteed to happen.

1) ctor

If allocation fails then no “raw memory” is there to initialize.

new int; // This won’t invoke any ctor since “int” is not a class/struct and doesn’t have a ctor.

2) allocation

It’s possible to bypass the allocation, if you use placement-new

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