pure-pure virtual invoked during base ctor/dtor #bbg

Update: P273 [[eff c#]] compares c# vs c++ when a pure virtual is invoked by ctor (book skips dtor). It confirms c++ would crash, but my bloodshed c++ compiler detected pure virtual called in base ctor and failed compilation. See source code at bottom.

This is rather obscure , not typical. Not even a valid question.

struct B{
 virtual void cleanup() = 0;
  }// not virtual
struct D: public B{
 void cleanup(){}
int main(){ D derivedObject; } 
// derivedObject destructed. 
// If (see below why impossible) code were to compile, what would happen here?

%%A: the invisible ~D() runs, then the defined ~B() runs even though it’s non-virtual.
%%A: I think it’s undefined behavior ONLY with “delete”.
%%A: virtual method called during base object destruction/construction – Warning by Scott Meyers. At time of base class destruction only the pure virtual is available, so system crashes saying “pure virtual function called”.

(In java, superclass ctor calling a virtual function results in the subclass’s version invoked, before the subclass ctor runs! Compiles but dangerous. If you do this, make sure the subclass ctor is empty.)

Q: how can a compiler intercept that error condition, with 0 runtime cost?
A: see post on pure pure virtual

Note, if Derived had not implemented the pure virtual, then Derived would have become an abstract class and non-instantiable.

Actually compiler detects the call to cleanup() is a call to B::cleanup() which is abstract. Here’s a demo.

struct B{
  virtual void cleanup() = 0;
  ~B();  // not virtual
//void B::cleanup(){       cout<<"B::cleanup\n";}
  cout<<"B()\n"; //this->cleanup(); //breaks compiler if enabled
  cout<<"~B()\n"; //this->cleanup(); //breaks compiler if enabled
struct D: public B{
  void cleanup(){       cout<<"D::cleanup\n"; }
  ~D(){cout<<"~D()\n"; }
int main(){
    if (true){
       D derivedObject; // derivedObject destructed. Suppose this can compile, what will happen?

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